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3x^2+25x+7=0
a = 3; b = 25; c = +7;
Δ = b2-4ac
Δ = 252-4·3·7
Δ = 541
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{541}}{2*3}=\frac{-25-\sqrt{541}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{541}}{2*3}=\frac{-25+\sqrt{541}}{6} $
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